Base | Representation |
---|---|
bin | 11111000100110111100… |
… | …010111110110011101111 |
3 | 21120011011210200220010212 |
4 | 133010313202332303233 |
5 | 234442031322210101 |
6 | 4313014345253035 |
7 | 310200304063544 |
oct | 37046742766357 |
9 | 7504153626125 |
10 | 2135530663151 |
11 | 753745428006 |
12 | 2a5a68a9417b |
13 | 1264c21c7642 |
14 | 755086b4bcb |
15 | 3a83b66b1bb |
hex | 1f1378becef |
2135530663151 has 2 divisors, whose sum is σ = 2135530663152. Its totient is φ = 2135530663150.
The previous prime is 2135530663121. The next prime is 2135530663153. The reversal of 2135530663151 is 1513660355312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2135530663151 - 210 = 2135530662127 is a prime.
It is a super-4 number, since 4×21355306631514 (a number of 50 digits) contains 4444 as substring.
Together with 2135530663153, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 2135530663099 and 2135530663108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2135530663153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1067765331575 + 1067765331576.
It is an arithmetic number, because the mean of its divisors is an integer number (1067765331576).
Almost surely, 22135530663151 is an apocalyptic number.
2135530663151 is a deficient number, since it is larger than the sum of its proper divisors (1).
2135530663151 is an equidigital number, since it uses as much as digits as its factorization.
2135530663151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 243000, while the sum is 41.
The spelling of 2135530663151 in words is "two trillion, one hundred thirty-five billion, five hundred thirty million, six hundred sixty-three thousand, one hundred fifty-one".
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