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2140011303 = 3713337101
BaseRepresentation
bin111111110001101…
…1111101100100111
312112010210211121220
41333203133230213
513340320330203
6552203511423
7104013540003
oct17743375447
95463724556
102140011303
119a8a87191
124b8828573
132814898a1
14164303703
15c7d1c653
hex7f8dfb27

2140011303 has 4 divisors (see below), whose sum is σ = 2853348408. Its totient is φ = 1426674200.

The previous prime is 2140011271. The next prime is 2140011311. The reversal of 2140011303 is 3031100412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2140011303 - 25 = 2140011271 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2140011353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356668548 + ... + 356668553.

It is an arithmetic number, because the mean of its divisors is an integer number (713337102).

Almost surely, 22140011303 is an apocalyptic number.

2140011303 is a deficient number, since it is larger than the sum of its proper divisors (713337105).

2140011303 is an equidigital number, since it uses as much as digits as its factorization.

2140011303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 713337104.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 2140011303 is about 46260.2561925461. The cubic root of 2140011303 is about 1288.6610113402.

Adding to 2140011303 its reverse (3031100412), we get a palindrome (5171111715).

The spelling of 2140011303 in words is "two billion, one hundred forty million, eleven thousand, three hundred three".

Divisors: 1 3 713337101 2140011303