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2140100133 = 31734123507
BaseRepresentation
bin111111110001111…
…0101011000100101
312112010222100110220
41333203311120211
513340331201013
6552205434553
7104014356663
oct17743653045
95463870426
102140100133
119a90379a6
124b886ba59
132814bb152
14164327c33
15c7d38b23
hex7f8f5625

2140100133 has 8 divisors (see below), whose sum is σ = 2869961568. Its totient is φ = 1418486064.

The previous prime is 2140100111. The next prime is 2140100173. The reversal of 2140100133 is 3310010412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2140100133 - 28 = 2140099877 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2140100173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2061235 + ... + 2062272.

It is an arithmetic number, because the mean of its divisors is an integer number (358745196).

Almost surely, 22140100133 is an apocalyptic number.

It is an amenable number.

2140100133 is a deficient number, since it is larger than the sum of its proper divisors (729861435).

2140100133 is a wasteful number, since it uses less digits than its factorization.

2140100133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4123683.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 2140100133 is about 46261.2162939973. The cubic root of 2140100133 is about 1288.6788414912.

Adding to 2140100133 its reverse (3310010412), we get a palindrome (5450110545).

The spelling of 2140100133 in words is "two billion, one hundred forty million, one hundred thousand, one hundred thirty-three".

Divisors: 1 3 173 519 4123507 12370521 713366711 2140100133