Base | Representation |
---|---|
bin | 1100011101010000011… |
… | …1110101101010110011 |
3 | 202110101212202022200110 |
4 | 3013110013311222303 |
5 | 12001244112102011 |
6 | 242152120352403 |
7 | 21314264605401 |
oct | 3072407655263 |
9 | 673355668613 |
10 | 214012222131 |
11 | 82842358074 |
12 | 35588315703 |
13 | 1724831a186 |
14 | a50305a471 |
15 | 58786bdba6 |
hex | 31d41f5ab3 |
214012222131 has 8 divisors (see below), whose sum is σ = 302134901904. Its totient is φ = 134282178560.
The previous prime is 214012222121. The next prime is 214012222133. The reversal of 214012222131 is 131222210412.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 214012222131 - 210 = 214012221107 is a prime.
It is a super-2 number, since 2×2140122221312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 214012222098 and 214012222107.
It is not an unprimeable number, because it can be changed into a prime (214012222133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2098158990 + ... + 2098159091.
It is an arithmetic number, because the mean of its divisors is an integer number (37766862738).
Almost surely, 2214012222131 is an apocalyptic number.
214012222131 is a deficient number, since it is larger than the sum of its proper divisors (88122679773).
214012222131 is a wasteful number, since it uses less digits than its factorization.
214012222131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4196318101.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 214012222131 its reverse (131222210412), we get a palindrome (345234432543).
The spelling of 214012222131 in words is "two hundred fourteen billion, twelve million, two hundred twenty-two thousand, one hundred thirty-one".
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