214013111420141 has 4 divisors (see below), whose sum is σ = 233468848821984. Its totient is φ = 194557374018300.

The previous prime is 214013111420083. The next prime is 214013111420149. The reversal of 214013111420141 is 141024111310412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 214013111420141 - 2⁶ = 214013111420077 is a prime.

It is a super-2 number, since 2×214013111420141² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 214013111420141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (214013111420149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9727868700905 + ... + 9727868700926.

It is an arithmetic number, because the mean of its divisors is an integer number (58367212205496).

Almost surely, 2^{214013111420141} is an apocalyptic number.

It is an amenable number.

214013111420141 is a deficient number, since it is larger than the sum of its proper divisors (19455737401843).

214013111420141 is a wasteful number, since it uses less digits than its factorization.

214013111420141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19455737401842.

The product of its (nonzero) digits is 768, while the sum is 26.

Adding to 214013111420141 its reverse (141024111310412), we get a palindrome (355037222730553).

The spelling of 214013111420141 in words is "two hundred fourteen trillion, thirteen billion, one hundred eleven million, four hundred twenty thousand, one hundred forty-one".