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21401312141 = 1110718182933
BaseRepresentation
bin10011111011100111…
…100001101110001101
32001020111100022010102
4103323213201232031
5322312213442031
613455344220445
71355226103016
oct237347415615
961214308112
1021401312141
119092534630
12419330a725
132030ac5711
14107045a00d
15853cbe7cb
hex4fb9e1b8d

21401312141 has 8 divisors (see below), whose sum is σ = 23565082464. Its totient is φ = 19273907920.

The previous prime is 21401312129. The next prime is 21401312147. The reversal of 21401312141 is 14121310412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21401312141 - 210 = 21401311117 is a prime.

It is a super-2 number, since 2×214013121412 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21401312147) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9090290 + ... + 9092643.

It is an arithmetic number, because the mean of its divisors is an integer number (2945635308).

Almost surely, 221401312141 is an apocalyptic number.

It is an amenable number.

21401312141 is a deficient number, since it is larger than the sum of its proper divisors (2163770323).

21401312141 is a wasteful number, since it uses less digits than its factorization.

21401312141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18183051.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 21401312141 its reverse (14121310412), we get a palindrome (35522622553).

The spelling of 21401312141 in words is "twenty-one billion, four hundred one million, three hundred twelve thousand, one hundred forty-one".

Divisors: 1 11 107 1177 18182933 200012263 1945573831 21401312141