21401533000650 has 96 divisors (see below), whose sum is σ = 57927456691200. Its totient is φ = 5185868529600.

The previous prime is 21401533000619. The next prime is 21401533000697. The reversal of 21401533000650 is 5600033510412.

It is a super-3 number, since 3×21401533000650³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 619071 + ... + 6571629.

It is an arithmetic number, because the mean of its divisors is an integer number (603411007200).

Almost surely, 2^{21401533000650} is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21401533000650, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (28963728345600).

21401533000650 is an abundant number, since it is smaller than the sum of its proper divisors (36525923690550).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21401533000650 is a wasteful number, since it uses less digits than its factorization.

21401533000650 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5954764 (or 5954759 counting only the distinct ones).

The product of its (nonzero) digits is 10800, while the sum is 30.

The spelling of 21401533000650 in words is "twenty-one trillion, four hundred one billion, five hundred thirty-three million, six hundred fifty", and thus it is an aban number.