Base | Representation |
---|---|
bin | 10011111011110011… |
… | …000111011000111101 |
3 | 2001020201001122022012 |
4 | 103323303013120331 |
5 | 322314003200023 |
6 | 13455533301005 |
7 | 1355263654544 |
oct | 237363073075 |
9 | 61221048265 |
10 | 21404350013 |
11 | 9094219a72 |
12 | 4194334765 |
13 | 203161a387 |
14 | 1070a0b15b |
15 | 8541be978 |
hex | 4fbcc763d |
21404350013 has 2 divisors, whose sum is σ = 21404350014. Its totient is φ = 21404350012.
The previous prime is 21404349971. The next prime is 21404350027. The reversal of 21404350013 is 31005340412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20654576089 + 749773924 = 143717^2 + 27382^2 .
It is a cyclic number.
It is not a de Polignac number, because 21404350013 - 210 = 21404348989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21404850013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10702175006 + 10702175007.
It is an arithmetic number, because the mean of its divisors is an integer number (10702175007).
Almost surely, 221404350013 is an apocalyptic number.
It is an amenable number.
21404350013 is a deficient number, since it is larger than the sum of its proper divisors (1).
21404350013 is an equidigital number, since it uses as much as digits as its factorization.
21404350013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 21404350013 its reverse (31005340412), we get a palindrome (52409690425).
The spelling of 21404350013 in words is "twenty-one billion, four hundred four million, three hundred fifty thousand, thirteen".
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