Base | Representation |
---|---|
bin | 110000101010110000010101… |
… | …101111110010011111001000 |
3 | 1001001212102220010100002221121 |
4 | 300222300111233302133020 |
5 | 211023400314340400202 |
6 | 2035122341430245024 |
7 | 63041123440244521 |
oct | 6052602557623710 |
9 | 1031772803302847 |
10 | 214044355012552 |
11 | 622237793093a9 |
12 | 2000b2914b6774 |
13 | 92583b060668c |
14 | 3abdb32bc7848 |
15 | 19b2bb8e73537 |
hex | c2ac15bf27c8 |
214044355012552 has 16 divisors (see below), whose sum is σ = 402814099843200. Its totient is φ = 106627261721040.
The previous prime is 214044355012549. The next prime is 214044355012573. The reversal of 214044355012552 is 255210553440412.
214044355012552 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 214044355012499 and 214044355012508.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49364470852 + ... + 49364475187.
It is an arithmetic number, because the mean of its divisors is an integer number (25175881240200).
Almost surely, 2214044355012552 is an apocalyptic number.
It is an amenable number.
214044355012552 is a deficient number, since it is larger than the sum of its proper divisors (188769744830648).
214044355012552 is a wasteful number, since it uses less digits than its factorization.
214044355012552 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98728946316 (or 98728946312 counting only the distinct ones).
The product of its (nonzero) digits is 960000, while the sum is 43.
The spelling of 214044355012552 in words is "two hundred fourteen trillion, forty-four billion, three hundred fifty-five million, twelve thousand, five hundred fifty-two".
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