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2141011255 = 51438929759
BaseRepresentation
bin111111110011101…
…0011110100110111
312112012200122022011
41333213103310313
513341044330010
6552241145051
7104025203215
oct17747236467
95465618264
102141011255
119a95aa499
124b902b187
13281749a86
141644c3cb5
15c7e68a8a
hex7f9d3d37

2141011255 has 8 divisors (see below), whose sum is σ = 2569478400. Its totient is φ = 1712632416.

The previous prime is 2141011193. The next prime is 2141011277. The reversal of 2141011255 is 5521101412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2141011255 - 211 = 2141009207 is a prime.

It is a super-3 number, since 3×21410112553 (a number of 29 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57066 + ... + 86824.

It is an arithmetic number, because the mean of its divisors is an integer number (321184800).

Almost surely, 22141011255 is an apocalyptic number.

2141011255 is a deficient number, since it is larger than the sum of its proper divisors (428467145).

2141011255 is a wasteful number, since it uses less digits than its factorization.

2141011255 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44153.

The product of its (nonzero) digits is 400, while the sum is 22.

The square root of 2141011255 is about 46271.0628254852. The cubic root of 2141011255 is about 1288.8616954052.

Adding to 2141011255 its reverse (5521101412), we get a palindrome (7662112667).

The spelling of 2141011255 in words is "two billion, one hundred forty-one million, eleven thousand, two hundred fifty-five".

Divisors: 1 5 14389 29759 71945 148795 428202251 2141011255