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2141131314012 = 223178427609501
BaseRepresentation
bin11111001010000101010…
…111110001001101011100
321120200122010022102210020
4133022011113301031130
5240040014104022022
64315342214512140
7310456141610655
oct37120527611534
97520563272706
102141131314012
11756059897989
122a6b70665650
13126ba561c132
14758ba44c52c
153aa681bd35c
hex1f2855f135c

2141131314012 has 12 divisors (see below), whose sum is σ = 4995973066056. Its totient is φ = 713710438000.

The previous prime is 2141131314001. The next prime is 2141131314037. The reversal of 2141131314012 is 2104131311412.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×21411313140122 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89213804739 + ... + 89213804762.

It is an arithmetic number, because the mean of its divisors is an integer number (416331088838).

Almost surely, 22141131314012 is an apocalyptic number.

It is an amenable number.

2141131314012 is an abundant number, since it is smaller than the sum of its proper divisors (2854841752044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2141131314012 is a wasteful number, since it uses less digits than its factorization.

2141131314012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 178427609508 (or 178427609506 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 2141131314012 its reverse (2104131311412), we get a palindrome (4245262625424).

The spelling of 2141131314012 in words is "two trillion, one hundred forty-one billion, one hundred thirty-one million, three hundred fourteen thousand, twelve".

Divisors: 1 2 3 4 6 12 178427609501 356855219002 535282828503 713710438004 1070565657006 2141131314012