Base | Representation |
---|---|
bin | 10011111100010000… |
… | …101110111011010101 |
3 | 2001021020200002200012 |
4 | 103330100232323111 |
5 | 322323000123013 |
6 | 13500411530005 |
7 | 1355416652504 |
oct | 237420567325 |
9 | 61236602605 |
10 | 21412114133 |
11 | 90986422a3 |
12 | 4196a59905 |
13 | 2033108327 |
14 | 1071a6c83b |
15 | 854c051a8 |
hex | 4fc42eed5 |
21412114133 has 2 divisors, whose sum is σ = 21412114134. Its totient is φ = 21412114132.
The previous prime is 21412114121. The next prime is 21412114147. The reversal of 21412114133 is 33141121412.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19050348529 + 2361765604 = 138023^2 + 48598^2 .
It is a cyclic number.
It is not a de Polignac number, because 21412114133 - 24 = 21412114117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21412114099 and 21412114108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21412113133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10706057066 + 10706057067.
It is an arithmetic number, because the mean of its divisors is an integer number (10706057067).
Almost surely, 221412114133 is an apocalyptic number.
It is an amenable number.
21412114133 is a deficient number, since it is larger than the sum of its proper divisors (1).
21412114133 is an equidigital number, since it uses as much as digits as its factorization.
21412114133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 576, while the sum is 23.
Adding to 21412114133 its reverse (33141121412), we get a palindrome (54553235545).
The spelling of 21412114133 in words is "twenty-one billion, four hundred twelve million, one hundred fourteen thousand, one hundred thirty-three".
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