Base | Representation |
---|---|
bin | 110000101100000100111110… |
… | …010100111011111010111111 |
3 | 1001002012010110100221112020021 |
4 | 300230010332110323322333 |
5 | 211031342422404334013 |
6 | 2035232211112033011 |
7 | 63050521424216251 |
oct | 6054047624737277 |
9 | 1032163410845207 |
10 | 214135230152383 |
11 | 62259271a21a51 |
12 | 20024a13392767 |
13 | 9263b33829977 |
14 | 3ac42b400dcd1 |
15 | 19b523706aa8d |
hex | c2c13e53bebf |
214135230152383 has 2 divisors, whose sum is σ = 214135230152384. Its totient is φ = 214135230152382.
The previous prime is 214135230152381. The next prime is 214135230152429. The reversal of 214135230152383 is 383251032531412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 214135230152383 - 21 = 214135230152381 is a prime.
Together with 214135230152381, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214135230152381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107067615076191 + 107067615076192.
It is an arithmetic number, because the mean of its divisors is an integer number (107067615076192).
Almost surely, 2214135230152383 is an apocalyptic number.
214135230152383 is a deficient number, since it is larger than the sum of its proper divisors (1).
214135230152383 is an equidigital number, since it uses as much as digits as its factorization.
214135230152383 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 43.
Adding to 214135230152383 its reverse (383251032531412), we get a palindrome (597386262683795).
The spelling of 214135230152383 in words is "two hundred fourteen trillion, one hundred thirty-five billion, two hundred thirty million, one hundred fifty-two thousand, three hundred eighty-three".
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