Base | Representation |
---|---|
bin | 11111001010010101101… |
… | …000010111110110001111 |
3 | 21120201100010121111121012 |
4 | 133022111220113312033 |
5 | 240041043422231111 |
6 | 4315425241355435 |
7 | 310465663353215 |
oct | 37122550276617 |
9 | 7521303544535 |
10 | 2141404102031 |
11 | 756189875627 |
12 | 2a7027a98b7b |
13 | 126c19cacc6c |
14 | 7590477acb5 |
15 | 3aa8210448b |
hex | 1f295a17d8f |
2141404102031 has 2 divisors, whose sum is σ = 2141404102032. Its totient is φ = 2141404102030.
The previous prime is 2141404102003. The next prime is 2141404102067. The reversal of 2141404102031 is 1302014041412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2141404102031 - 214 = 2141404085647 is a prime.
It is a super-2 number, since 2×21414041020312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2141404101988 and 2141404102006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2141404108031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070702051015 + 1070702051016.
It is an arithmetic number, because the mean of its divisors is an integer number (1070702051016).
Almost surely, 22141404102031 is an apocalyptic number.
2141404102031 is a deficient number, since it is larger than the sum of its proper divisors (1).
2141404102031 is an equidigital number, since it uses as much as digits as its factorization.
2141404102031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 2141404102031 its reverse (1302014041412), we get a palindrome (3443418143443).
The spelling of 2141404102031 in words is "two trillion, one hundred forty-one billion, four hundred four million, one hundred two thousand, thirty-one".
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