Base | Representation |
---|---|
bin | 11111001010010110001… |
… | …110001011000111001101 |
3 | 21120201100211020221121200 |
4 | 133022112032023013031 |
5 | 240041103441330331 |
6 | 4315430234020113 |
7 | 310466143524303 |
oct | 37122616130715 |
9 | 7521324227550 |
10 | 2141414011341 |
11 | 756194423640 |
12 | 2a702b277639 |
13 | 126c1c06c467 |
14 | 75905bda273 |
15 | 3aa82e105e6 |
hex | 1f29638b1cd |
2141414011341 has 48 divisors (see below), whose sum is σ = 3383777125248. Its totient is φ = 1294202448000.
The previous prime is 2141414011339. The next prime is 2141414011349. The reversal of 2141414011341 is 1431104141412.
2141414011341 is a `hidden beast` number, since 214 + 1 + 4 + 1 + 401 + 1 + 3 + 41 = 666.
It is not a de Polignac number, because 2141414011341 - 21 = 2141414011339 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2141414011349) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 247643880 + ... + 247652526.
It is an arithmetic number, because the mean of its divisors is an integer number (70495356776).
Almost surely, 22141414011341 is an apocalyptic number.
It is an amenable number.
2141414011341 is a deficient number, since it is larger than the sum of its proper divisors (1242363113907).
2141414011341 is a wasteful number, since it uses less digits than its factorization.
2141414011341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15362 (or 15359 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 27.
Adding to 2141414011341 its reverse (1431104141412), we get a palindrome (3572518152753).
The spelling of 2141414011341 in words is "two trillion, one hundred forty-one billion, four hundred fourteen million, eleven thousand, three hundred forty-one".
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