Base | Representation |
---|---|
bin | 1100011110000000010… |
… | …0000000001011000101 |
3 | 202110220211200200111022 |
4 | 3013200010000023011 |
5 | 12002201402340143 |
6 | 242224034120525 |
7 | 21322246400636 |
oct | 3074004001305 |
9 | 673824620438 |
10 | 214212543173 |
11 | 8293543a252 |
12 | 35623420145 |
13 | 1727a987635 |
14 | a5218c388d |
15 | 588b08d268 |
hex | 31e01002c5 |
214212543173 has 2 divisors, whose sum is σ = 214212543174. Its totient is φ = 214212543172.
The previous prime is 214212543109. The next prime is 214212543211. The reversal of 214212543173 is 371345212412.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 151288325764 + 62924217409 = 388958^2 + 250847^2 .
It is a cyclic number.
It is not a de Polignac number, because 214212543173 - 26 = 214212543109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214212543073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107106271586 + 107106271587.
It is an arithmetic number, because the mean of its divisors is an integer number (107106271587).
Almost surely, 2214212543173 is an apocalyptic number.
It is an amenable number.
214212543173 is a deficient number, since it is larger than the sum of its proper divisors (1).
214212543173 is an equidigital number, since it uses as much as digits as its factorization.
214212543173 is an evil number, because the sum of its binary digits is even.
The product of its digits is 40320, while the sum is 35.
Adding to 214212543173 its reverse (371345212412), we get a palindrome (585557755585).
The spelling of 214212543173 in words is "two hundred fourteen billion, two hundred twelve million, five hundred forty-three thousand, one hundred seventy-three".
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