Search a number
-
+
21431113001 = 47699449299
BaseRepresentation
bin10011111101011001…
…001101010100101001
32001022120102100012222
4103331121031110221
5322342331104001
613502331043425
71356040312004
oct237531152451
961276370188
1021431113001
1190a8339441
1241a12a0575
13203702ab6c
1410743b653b
1585670961b
hex4fd64d529

21431113001 has 4 divisors (see below), whose sum is σ = 21431610000. Its totient is φ = 21430616004.

The previous prime is 21431112961. The next prime is 21431113049. The reversal of 21431113001 is 10031113412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21431113001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21431119001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 176951 + ... + 272348.

It is an arithmetic number, because the mean of its divisors is an integer number (5357902500).

Almost surely, 221431113001 is an apocalyptic number.

It is an amenable number.

21431113001 is a deficient number, since it is larger than the sum of its proper divisors (496999).

21431113001 is an equidigital number, since it uses as much as digits as its factorization.

21431113001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 496998.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 21431113001 its reverse (10031113412), we get a palindrome (31462226413).

The spelling of 21431113001 in words is "twenty-one billion, four hundred thirty-one million, one hundred thirteen thousand, one".

Divisors: 1 47699 449299 21431113001