21433100399 has 2 divisors, whose sum is σ = 21433100400. Its totient is φ = 21433100398.

The previous prime is 21433100281. The next prime is 21433100401. The reversal of 21433100399 is 99300133412.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21433100399 - 2²⁴ = 21416323183 is a prime.

It is a super-2 number, since 2×21433100399² (a number of 21 digits) contains 22 as substring.

Together with 21433100401, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21433108399) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10716550199 + 10716550200.

It is an arithmetic number, because the mean of its divisors is an integer number (10716550200).

Almost surely, 2^21433100399 is an apocalyptic number.

21433100399 is a deficient number, since it is larger than the sum of its proper divisors (1).

21433100399 is an equidigital number, since it uses as much as digits as its factorization.

21433100399 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17496, while the sum is 35.

The spelling of 21433100399 in words is "twenty-one billion, four hundred thirty-three million, one hundred thousand, three hundred ninety-nine".