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214331114021 = 823260426627
BaseRepresentation
bin1100011110011100100…
…0010100001000100101
3202111020002210201010012
43013213020110020211
512002422231122041
6242243511340005
721325216260353
oct3074710241045
9674202721105
10214331114021
1182996365292
1235657081605
1317299400bbb
14a53354a7d3
1558966b03eb
hex31e7214225

214331114021 has 4 divisors (see below), whose sum is σ = 214591541472. Its totient is φ = 214070686572.

The previous prime is 214331113987. The next prime is 214331114089. The reversal of 214331114021 is 120411133412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-214331114021 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (214331144021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130212491 + ... + 130214136.

It is an arithmetic number, because the mean of its divisors is an integer number (53647885368).

Almost surely, 2214331114021 is an apocalyptic number.

It is an amenable number.

214331114021 is a deficient number, since it is larger than the sum of its proper divisors (260427451).

214331114021 is an equidigital number, since it uses as much as digits as its factorization.

214331114021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 260427450.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 214331114021 its reverse (120411133412), we get a palindrome (334742247433).

The spelling of 214331114021 in words is "two hundred fourteen billion, three hundred thirty-one million, one hundred fourteen thousand, twenty-one".

Divisors: 1 823 260426627 214331114021