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2143312111 = 17671881749
BaseRepresentation
bin111111111000000…
…0101100011101111
312112101000112111001
41333300011203233
513342141441421
6552402341131
7104053565233
oct17760054357
95471015431
102143312111
119aa931126
124b995a7a7
13282074125
141649225c3
15c8270691
hex7fc058ef

2143312111 has 8 divisors (see below), whose sum is σ = 2303262000. Its totient is φ = 1987125888.

The previous prime is 2143312099. The next prime is 2143312121. The reversal of 2143312111 is 1112133412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2143312111 - 213 = 2143303919 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2143312121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 939736 + ... + 942013.

It is an arithmetic number, because the mean of its divisors is an integer number (287907750).

Almost surely, 22143312111 is an apocalyptic number.

2143312111 is a deficient number, since it is larger than the sum of its proper divisors (159949889).

2143312111 is a wasteful number, since it uses less digits than its factorization.

2143312111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1881833.

The product of its digits is 144, while the sum is 19.

The square root of 2143312111 is about 46295.9189454103. The cubic root of 2143312111 is about 1289.3232255190.

Adding to 2143312111 its reverse (1112133412), we get a palindrome (3255445523).

The spelling of 2143312111 in words is "two billion, one hundred forty-three million, three hundred twelve thousand, one hundred eleven".

Divisors: 1 17 67 1139 1881749 31989733 126077183 2143312111