2143330181 has 2 divisors, whose sum is σ = 2143330182. Its totient is φ = 2143330180.

The previous prime is 2143330127. The next prime is 2143330183. The reversal of 2143330181 is 1810333412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1196537281 + 946792900 = 34591^2 + 30770^2 .

It is a cyclic number.

It is not a de Polignac number, because 2143330181 - 2¹⁰ = 2143329157 is a prime.

It is a super-2 number, since 2×2143330181² = 9187728529570985522, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 2143330183, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 2143330181.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2143330183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1071665090 + 1071665091.

It is an arithmetic number, because the mean of its divisors is an integer number (1071665091).

Almost surely, 2^2143330181 is an apocalyptic number.

It is an amenable number.

2143330181 is a deficient number, since it is larger than the sum of its proper divisors (1).

2143330181 is an equidigital number, since it uses as much as digits as its factorization.

2143330181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 26.

The square root of 2143330181 is about 46296.1141025896. The cubic root of 2143330181 is about 1289.3268488838.

Adding to 2143330181 its reverse (1810333412), we get a palindrome (3953663593).

The spelling of 2143330181 in words is "two billion, one hundred forty-three million, three hundred thirty thousand, one hundred eighty-one".