214343111311133 has 4 divisors (see below), whose sum is σ = 244963555784160. Its totient is φ = 183722666838108.

The previous prime is 214343111311129. The next prime is 214343111311141. The reversal of 214343111311133 is 331113111343412.

214343111311133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 214343111311133 - 2² = 214343111311129 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 214343111311133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (214343111319133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15310222236503 + ... + 15310222236516.

It is an arithmetic number, because the mean of its divisors is an integer number (61240888946040).

Almost surely, 2^{214343111311133} is an apocalyptic number.

It is an amenable number.

214343111311133 is a deficient number, since it is larger than the sum of its proper divisors (30620444473027).

214343111311133 is an equidigital number, since it uses as much as digits as its factorization.

214343111311133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30620444473026.

The product of its digits is 7776, while the sum is 32.

Adding to 214343111311133 its reverse (331113111343412), we get a palindrome (545456222654545).

The spelling of 214343111311133 in words is "two hundred fourteen trillion, three hundred forty-three billion, one hundred eleven million, three hundred eleven thousand, one hundred thirty-three".