214343111311132 has 12 divisors (see below), whose sum is σ = 375124289570856. Its totient is φ = 107164742862320.

The previous prime is 214343111311129. The next prime is 214343111311141. The reversal of 214343111311132 is 231113111343412.

It is a junction number, because it is equal to n+sod(n) for n = 214343111311094 and 214343111311103.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1703127523 + ... + 1703253370.

It is an arithmetic number, because the mean of its divisors is an integer number (31260357464238).

Almost surely, 2^{214343111311132} is an apocalyptic number.

It is an amenable number.

214343111311132 is a deficient number, since it is larger than the sum of its proper divisors (160781178259724).

214343111311132 is a wasteful number, since it uses less digits than its factorization.

214343111311132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3406396628 (or 3406396626 counting only the distinct ones).

The product of its digits is 5184, while the sum is 31.

Adding to 214343111311132 its reverse (231113111343412), we get a palindrome (445456222654544).

The spelling of 214343111311132 in words is "two hundred fourteen trillion, three hundred forty-three billion, one hundred eleven million, three hundred eleven thousand, one hundred thirty-two".