Base | Representation |
---|---|
bin | 11001100011010… |
… | …10000110110001 |
3 | 112221022210211212 |
4 | 30301222012301 |
5 | 414333002423 |
6 | 33134045505 |
7 | 5211615644 |
oct | 1461520661 |
9 | 487283755 |
10 | 214344113 |
11 | aaa9a9a5 |
12 | 5b949895 |
13 | 3553a249 |
14 | 20677a5b |
15 | 13c3e578 |
hex | cc6a1b1 |
214344113 has 2 divisors, whose sum is σ = 214344114. Its totient is φ = 214344112.
The previous prime is 214344049. The next prime is 214344131. The reversal of 214344113 is 311443412.
Together with next prime (214344131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 213510544 + 833569 = 14612^2 + 913^2 .
It is a cyclic number.
It is not a de Polignac number, because 214344113 - 26 = 214344049 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (214344413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107172056 + 107172057.
It is an arithmetic number, because the mean of its divisors is an integer number (107172057).
Almost surely, 2214344113 is an apocalyptic number.
It is an amenable number.
214344113 is a deficient number, since it is larger than the sum of its proper divisors (1).
214344113 is an equidigital number, since it uses as much as digits as its factorization.
214344113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1152, while the sum is 23.
The square root of 214344113 is about 14640.4956541778. The cubic root of 214344113 is about 598.4628365402.
Adding to 214344113 its reverse (311443412), we get a palindrome (525787525).
The spelling of 214344113 in words is "two hundred fourteen million, three hundred forty-four thousand, one hundred thirteen".
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