Base | Representation |
---|---|
bin | 10011111101101100… |
… | …100111010011010111 |
3 | 2001022220222210110221 |
4 | 103331230213103113 |
5 | 322400131401101 |
6 | 13503032055211 |
7 | 1356131460232 |
oct | 237554472327 |
9 | 61286883427 |
10 | 21436200151 |
11 | 91001a34a3 |
12 | 41a2b34507 |
13 | 20380bc502 |
14 | 1074d3c419 |
15 | 856db1aa1 |
hex | 4fdb274d7 |
21436200151 has 2 divisors, whose sum is σ = 21436200152. Its totient is φ = 21436200150.
The previous prime is 21436200139. The next prime is 21436200161. The reversal of 21436200151 is 15100263412.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21436200151 - 25 = 21436200119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21436200131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10718100075 + 10718100076.
It is an arithmetic number, because the mean of its divisors is an integer number (10718100076).
Almost surely, 221436200151 is an apocalyptic number.
21436200151 is a deficient number, since it is larger than the sum of its proper divisors (1).
21436200151 is an equidigital number, since it uses as much as digits as its factorization.
21436200151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 21436200151 its reverse (15100263412), we get a palindrome (36536463563).
The spelling of 21436200151 in words is "twenty-one billion, four hundred thirty-six million, two hundred thousand, one hundred fifty-one".
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