Base | Representation |
---|---|
bin | 110000101111110110101111… |
… | …101101000010110100001111 |
3 | 1001010002221112100111012110211 |
4 | 300233312233231002310033 |
5 | 211100121103031211442 |
6 | 2035551343024543251 |
7 | 63105341521320322 |
oct | 6057665755026417 |
9 | 1033087470435424 |
10 | 214394830335247 |
11 | 6234937850a721 |
12 | 200671a2a81b27 |
13 | 92824657c9a23 |
14 | 3ad2a9d82a7b9 |
15 | 19bbd7cab8617 |
hex | c2fdafb42d0f |
214394830335247 has 2 divisors, whose sum is σ = 214394830335248. Its totient is φ = 214394830335246.
The previous prime is 214394830335241. The next prime is 214394830335253. The reversal of 214394830335247 is 742533038493412.
It is a balanced prime because it is at equal distance from previous prime (214394830335241) and next prime (214394830335253).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-214394830335247 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 214394830335191 and 214394830335200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214394830335241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107197415167623 + 107197415167624.
It is an arithmetic number, because the mean of its divisors is an integer number (107197415167624).
Almost surely, 2214394830335247 is an apocalyptic number.
214394830335247 is a deficient number, since it is larger than the sum of its proper divisors (1).
214394830335247 is an equidigital number, since it uses as much as digits as its factorization.
214394830335247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52254720, while the sum is 58.
The spelling of 214394830335247 in words is "two hundred fourteen trillion, three hundred ninety-four billion, eight hundred thirty million, three hundred thirty-five thousand, two hundred forty-seven".
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