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214415043431 is a prime number
BaseRepresentation
bin1100011110110000100…
…0011110101101100111
3202111102221201202121212
43013230020132231213
512003110222342211
6242300110302035
721330255540461
oct3075410365547
9674387652555
10214415043431
1182a2977a736
123567b1b791b
13172b0908984
14a540757131
15589dc3d38b
hex31ec21eb67

214415043431 has 2 divisors, whose sum is σ = 214415043432. Its totient is φ = 214415043430.

The previous prime is 214415043389. The next prime is 214415043433. The reversal of 214415043431 is 134340514412.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-214415043431 is a prime.

It is a super-2 number, since 2×2144150434312 (a number of 23 digits) contains 22 as substring.

Together with 214415043433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (214415043433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107207521715 + 107207521716.

It is an arithmetic number, because the mean of its divisors is an integer number (107207521716).

Almost surely, 2214415043431 is an apocalyptic number.

214415043431 is a deficient number, since it is larger than the sum of its proper divisors (1).

214415043431 is an equidigital number, since it uses as much as digits as its factorization.

214415043431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 214415043431 its reverse (134340514412), we get a palindrome (348755557843).

The spelling of 214415043431 in words is "two hundred fourteen billion, four hundred fifteen million, forty-three thousand, four hundred thirty-one".