Base | Representation |
---|---|
bin | 11111001100111111011… |
… | …101101101110010101011 |
3 | 21120222200201010121200210 |
4 | 133030333131231302223 |
5 | 240112412334410201 |
6 | 4321020104432203 |
7 | 310626412320450 |
oct | 37147735556253 |
9 | 7528621117623 |
10 | 2144253435051 |
11 | 757411188702 |
12 | 2a76a2178663 |
13 | 1272823c0b30 |
14 | 75ad4d63827 |
15 | 3ab9c3361d6 |
hex | 1f33f76dcab |
2144253435051 has 64 divisors (see below), whose sum is σ = 3738655872000. Its totient is φ = 1064502655488.
The previous prime is 2144253435047. The next prime is 2144253435053. The reversal of 2144253435051 is 1505343524412.
It is not a de Polignac number, because 2144253435051 - 22 = 2144253435047 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is not an unprimeable number, because it can be changed into a prime (2144253435053) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 541900 + ... + 2140598.
It is an arithmetic number, because the mean of its divisors is an integer number (58416498000).
Almost surely, 22144253435051 is an apocalyptic number.
2144253435051 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
2144253435051 is a deficient number, since it is larger than the sum of its proper divisors (1594402436949).
2144253435051 is a wasteful number, since it uses less digits than its factorization.
2144253435051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1598773 (or 1598739 counting only the distinct ones).
The product of its (nonzero) digits is 288000, while the sum is 39.
Adding to 2144253435051 its reverse (1505343524412), we get a palindrome (3649596959463).
The spelling of 2144253435051 in words is "two trillion, one hundred forty-four billion, two hundred fifty-three million, four hundred thirty-five thousand, fifty-one".
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