21443141113501 has 4 divisors (see below), whose sum is σ = 21443151773052. Its totient is φ = 21443130453952.

The previous prime is 21443141113489. The next prime is 21443141113519. The reversal of 21443141113501 is 10531114134412.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 9408666696025 + 12034474417476 = 3067355^2 + 3469074^2 .

It is a cyclic number.

It is not a de Polignac number, because 21443141113501 - 2⁵ = 21443141113469 is a prime.

It is a super-3 number, since 3×21443141113501³ (a number of 41 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21443141123501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1293340 + ... + 6675253.

It is an arithmetic number, because the mean of its divisors is an integer number (5360787943263).

Almost surely, 2^{21443141113501} is an apocalyptic number.

It is an amenable number.

21443141113501 is a deficient number, since it is larger than the sum of its proper divisors (10659551).

21443141113501 is an equidigital number, since it uses as much as digits as its factorization.

21443141113501 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10659550.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 21443141113501 its reverse (10531114134412), we get a palindrome (31974255247913).

The spelling of 21443141113501 in words is "twenty-one trillion, four hundred forty-three billion, one hundred forty-one million, one hundred thirteen thousand, five hundred one".