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2145651413471 is a prime number
BaseRepresentation
bin11111001110010010110…
…010100101000111011111
321121010022010200021120022
4133032102302211013133
5240123243230212341
64321410524142355
7311006146043336
oct37162262450737
97533263607508
102145651413471
11757a69316575
122a7a123979bb
13127445c123b7
1475bc88aad1d
153ac2ee2be4b
hex1f392ca51df

2145651413471 has 2 divisors, whose sum is σ = 2145651413472. Its totient is φ = 2145651413470.

The previous prime is 2145651413443. The next prime is 2145651413473. The reversal of 2145651413471 is 1743141565412.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2145651413471 - 218 = 2145651151327 is a prime.

It is a super-3 number, since 3×21456514134713 (a number of 38 digits) contains 333 as substring.

Together with 2145651413473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2145651413473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1072825706735 + 1072825706736.

It is an arithmetic number, because the mean of its divisors is an integer number (1072825706736).

Almost surely, 22145651413471 is an apocalyptic number.

2145651413471 is a deficient number, since it is larger than the sum of its proper divisors (1).

2145651413471 is an equidigital number, since it uses as much as digits as its factorization.

2145651413471 is an evil number, because the sum of its binary digits is even.

The product of its digits is 403200, while the sum is 44.

Adding to 2145651413471 its reverse (1743141565412), we get a palindrome (3888792978883).

The spelling of 2145651413471 in words is "two trillion, one hundred forty-five billion, six hundred fifty-one million, four hundred thirteen thousand, four hundred seventy-one".