21471471341 has 4 divisors (see below), whose sum is σ = 22601548800. Its totient is φ = 20341393884.

The previous prime is 21471471311. The next prime is 21471471347. The reversal of 21471471341 is 14317417412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21471471341 - 2¹⁸ = 21471209197 is a prime.

It is a super-2 number, since 2×21471471341² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21471471347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 565038701 + ... + 565038738.

It is an arithmetic number, because the mean of its divisors is an integer number (5650387200).

Almost surely, 2^21471471341 is an apocalyptic number.

It is an amenable number.

21471471341 is a deficient number, since it is larger than the sum of its proper divisors (1130077459).

21471471341 is a wasteful number, since it uses less digits than its factorization.

21471471341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1130077458.

The product of its digits is 18816, while the sum is 35.

Adding to 21471471341 its reverse (14317417412), we get a palindrome (35788888753).

The spelling of 21471471341 in words is "twenty-one billion, four hundred seventy-one million, four hundred seventy-one thousand, three hundred forty-one".