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2147333542117 is a prime number
BaseRepresentation
bin11111001111110111000…
…011011001000011100101
321121021122100220021021021
4133033313003121003211
5240140214341321432
64322245454051141
7311065632643441
oct37176703310345
97537570807237
102147333542117
11758751892735
122a82017a9ab1
131276535723aa
1475d0805d821
153accc950697
hex1f3f70d90e5

2147333542117 has 2 divisors, whose sum is σ = 2147333542118. Its totient is φ = 2147333542116.

The previous prime is 2147333542069. The next prime is 2147333542199. The reversal of 2147333542117 is 7112453337412.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1959143293636 + 188190248481 = 1399694^2 + 433809^2 .

It is a cyclic number.

It is not a de Polignac number, because 2147333542117 - 211 = 2147333540069 is a prime.

It is a super-3 number, since 3×21473335421173 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2147333545117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1073666771058 + 1073666771059.

It is an arithmetic number, because the mean of its divisors is an integer number (1073666771059).

Almost surely, 22147333542117 is an apocalyptic number.

It is an amenable number.

2147333542117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2147333542117 is an equidigital number, since it uses as much as digits as its factorization.

2147333542117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 423360, while the sum is 43.

Adding to 2147333542117 its reverse (7112453337412), we get a palindrome (9259786879529).

The spelling of 2147333542117 in words is "two trillion, one hundred forty-seven billion, three hundred thirty-three million, five hundred forty-two thousand, one hundred seventeen".