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2147333542142 = 21073666771071
BaseRepresentation
bin11111001111110111000…
…011011001000011111110
321121021122100220021022012
4133033313003121003332
5240140214341322032
64322245454051222
7311065632643505
oct37176703310376
97537570807265
102147333542142
11758751892758
122a82017a9b12
131276535723c9
1475d0805d83c
153accc9506b2
hex1f3f70d90fe

2147333542142 has 4 divisors (see below), whose sum is σ = 3221000313216. Its totient is φ = 1073666771070.

The previous prime is 2147333542117. The next prime is 2147333542199. The reversal of 2147333542142 is 2412453337412.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×21473335421422 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2147333542142.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 536833385534 + ... + 536833385537.

It is an arithmetic number, because the mean of its divisors is an integer number (805250078304).

Almost surely, 22147333542142 is an apocalyptic number.

2147333542142 is a deficient number, since it is larger than the sum of its proper divisors (1073666771074).

2147333542142 is a wasteful number, since it uses less digits than its factorization.

2147333542142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1073666771073.

The product of its digits is 483840, while the sum is 41.

Adding to 2147333542142 its reverse (2412453337412), we get a palindrome (4559786879554).

The spelling of 2147333542142 in words is "two trillion, one hundred forty-seven billion, three hundred thirty-three million, five hundred forty-two thousand, one hundred forty-two".

Divisors: 1 2 1073666771071 2147333542142