Base | Representation |
---|---|
bin | 1001110001101111000110… |
… | …01110000100100001010101 |
3 | 2211010101120120100200200120 |
4 | 10320313203032010201111 |
5 | 10304224223044324140 |
6 | 113421004221302153 |
7 | 4346222046560355 |
oct | 470674316044125 |
9 | 84111516320616 |
10 | 21500123433045 |
11 | 693a173197504 |
12 | 24b2a4ba04959 |
13 | bcc5b7156a3a |
14 | 54487c058b65 |
15 | 274402eb31d0 |
hex | 138de3384855 |
21500123433045 has 8 divisors (see below), whose sum is σ = 34400197492896. Its totient is φ = 11466732497616.
The previous prime is 21500123433037. The next prime is 21500123433067. The reversal of 21500123433045 is 54033432100512.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 21500123433045 - 23 = 21500123433037 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21500123432997 and 21500123433015.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 716670781087 + ... + 716670781116.
It is an arithmetic number, because the mean of its divisors is an integer number (4300024686612).
Almost surely, 221500123433045 is an apocalyptic number.
It is an amenable number.
21500123433045 is a deficient number, since it is larger than the sum of its proper divisors (12900074059851).
21500123433045 is a wasteful number, since it uses less digits than its factorization.
21500123433045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1433341562211.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 21500123433045 its reverse (54033432100512), we get a palindrome (75533555533557).
The spelling of 21500123433045 in words is "twenty-one trillion, five hundred billion, one hundred twenty-three million, four hundred thirty-three thousand, forty-five".
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