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215050214101 is a prime number
BaseRepresentation
bin1100100001000111111…
…1011101101011010101
3202120002012220202222111
43020101333131223111
512010410323322401
6242443120231021
721352100442142
oct3102177355325
9676065822874
10215050214101
118322526a878
1235817a6b471
1317382399bc8
14a5a0c573c9
1558d98a6e51
hex3211fddad5

215050214101 has 2 divisors, whose sum is σ = 215050214102. Its totient is φ = 215050214100.

The previous prime is 215050214083. The next prime is 215050214123. The reversal of 215050214101 is 101412050512.

It is an a-pointer prime, because the next prime (215050214123) can be obtained adding 215050214101 to its sum of digits (22).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111989953201 + 103060260900 = 334649^2 + 321030^2 .

It is a cyclic number.

It is not a de Polignac number, because 215050214101 - 25 = 215050214069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (215050214161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107525107050 + 107525107051.

It is an arithmetic number, because the mean of its divisors is an integer number (107525107051).

Almost surely, 2215050214101 is an apocalyptic number.

It is an amenable number.

215050214101 is a deficient number, since it is larger than the sum of its proper divisors (1).

215050214101 is an equidigital number, since it uses as much as digits as its factorization.

215050214101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 400, while the sum is 22.

Adding to 215050214101 its reverse (101412050512), we get a palindrome (316462264613).

The spelling of 215050214101 in words is "two hundred fifteen billion, fifty million, two hundred fourteen thousand, one hundred one".