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215070325133 is a prime number
BaseRepresentation
bin1100100001001100110…
…0001011100110001101
3202120010121202112010112
43020103030023212031
512010431000401013
6242445115245405
721352433412656
oct3102314134615
9676117675115
10215070325133
1183235656564
1235822749865
13173865bba21
14a5a37b052d
1558db52aba8
hex321330b98d

215070325133 has 2 divisors, whose sum is σ = 215070325134. Its totient is φ = 215070325132.

The previous prime is 215070325121. The next prime is 215070325157. The reversal of 215070325133 is 331523070512.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 202776394249 + 12293930884 = 450307^2 + 110878^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-215070325133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 215070325133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (215070325163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107535162566 + 107535162567.

It is an arithmetic number, because the mean of its divisors is an integer number (107535162567).

Almost surely, 2215070325133 is an apocalyptic number.

It is an amenable number.

215070325133 is a deficient number, since it is larger than the sum of its proper divisors (1).

215070325133 is an equidigital number, since it uses as much as digits as its factorization.

215070325133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18900, while the sum is 32.

Adding to 215070325133 its reverse (331523070512), we get a palindrome (546593395645).

The spelling of 215070325133 in words is "two hundred fifteen billion, seventy million, three hundred twenty-five thousand, one hundred thirty-three".