Base | Representation |
---|---|
bin | 11111010011010001111… |
… | …001000000101110010111 |
3 | 21121122010020110020121211 |
4 | 133103101321000232113 |
5 | 240220224242000234 |
6 | 4324054050522251 |
7 | 311255624043544 |
oct | 37232171005627 |
9 | 7548106406554 |
10 | 2151005031319 |
11 | 75a266299931 |
12 | 2a8a67296387 |
13 | 127aba0c2b01 |
14 | 761758dbbcb |
15 | 3ae44e34164 |
hex | 1f4d1e40b97 |
2151005031319 has 4 divisors (see below), whose sum is σ = 2151022155544. Its totient is φ = 2150987907096.
The previous prime is 2151005031313. The next prime is 2151005031347. The reversal of 2151005031319 is 9131305001512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2151005031319 - 23 = 2151005031311 is a prime.
It is a super-2 number, since 2×21510050313192 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2151005031311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8372292 + ... + 8625385.
It is an arithmetic number, because the mean of its divisors is an integer number (537755538886).
Almost surely, 22151005031319 is an apocalyptic number.
2151005031319 is a deficient number, since it is larger than the sum of its proper divisors (17124225).
2151005031319 is a wasteful number, since it uses less digits than its factorization.
2151005031319 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17124224.
The product of its (nonzero) digits is 4050, while the sum is 31.
The spelling of 2151005031319 in words is "two trillion, one hundred fifty-one billion, five million, thirty-one thousand, three hundred nineteen".
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