Base | Representation |
---|---|
bin | 1001110010000001111010… |
… | …00010100111011000010010 |
3 | 2211011100122020102101200021 |
4 | 10321000331002213120102 |
5 | 10304410412400023010 |
6 | 113425354144414054 |
7 | 4350030211624432 |
oct | 471007502473022 |
9 | 84140566371607 |
10 | 21510220314130 |
11 | 6943484662729 |
12 | 24b49a931732a |
13 | c00535c351a2 |
14 | 545158dda2c2 |
15 | 2747e460b8da |
hex | 13903d0a7612 |
21510220314130 has 64 divisors (see below), whose sum is σ = 40653819181440. Its totient is φ = 8182902841344.
The previous prime is 21510220314113. The next prime is 21510220314131. The reversal of 21510220314130 is 3141302201512.
It is a junction number, because it is equal to n+sod(n) for n = 21510220314095 and 21510220314104.
It is not an unprimeable number, because it can be changed into a prime (21510220314131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 530088402 + ... + 530128978.
It is an arithmetic number, because the mean of its divisors is an integer number (635215924710).
Almost surely, 221510220314130 is an apocalyptic number.
21510220314130 is a deficient number, since it is larger than the sum of its proper divisors (19143598867310).
21510220314130 is a wasteful number, since it uses less digits than its factorization.
21510220314130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67963.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 21510220314130 its reverse (3141302201512), we get a palindrome (24651522515642).
The spelling of 21510220314130 in words is "twenty-one trillion, five hundred ten billion, two hundred twenty million, three hundred fourteen thousand, one hundred thirty".
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