Base | Representation |
---|---|
bin | 11111010011011111111… |
… | …101010100000010110111 |
3 | 21121122201200112201202010 |
4 | 133103133331110002313 |
5 | 240221220201240210 |
6 | 4324133321215303 |
7 | 311264521063632 |
oct | 37233775240267 |
9 | 7548650481663 |
10 | 2151241040055 |
11 | 75a377536778 |
12 | 2a8b12331533 |
13 | 127b26c77053 |
14 | 76198db4c19 |
15 | 3ae5aa02920 |
hex | 1f4dff540b7 |
2151241040055 has 32 divisors (see below), whose sum is σ = 3467442585600. Its totient is φ = 1138846223232.
The previous prime is 2151241040041. The next prime is 2151241040083. The reversal of 2151241040055 is 5500401421512.
It is not a de Polignac number, because 2151241040055 - 29 = 2151241039543 is a prime.
It is a super-2 number, since 2×21512410400552 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10572337 + ... + 10773893.
It is an arithmetic number, because the mean of its divisors is an integer number (108357580800).
Almost surely, 22151241040055 is an apocalyptic number.
2151241040055 is a deficient number, since it is larger than the sum of its proper divisors (1316201545545).
2151241040055 is a wasteful number, since it uses less digits than its factorization.
2151241040055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 206823.
The product of its (nonzero) digits is 8000, while the sum is 30.
Adding to 2151241040055 its reverse (5500401421512), we get a palindrome (7651642461567).
The spelling of 2151241040055 in words is "two trillion, one hundred fifty-one billion, two hundred forty-one million, forty thousand, fifty-five".
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