Base | Representation |
---|---|
bin | 1001110010000110001101… |
… | …01101010111100101111111 |
3 | 2211011120121012111121101211 |
4 | 10321003012231113211333 |
5 | 10304430130140002010 |
6 | 113430415253145251 |
7 | 4350141355630300 |
oct | 471030655274577 |
9 | 84146535447354 |
10 | 21512530000255 |
11 | 694445a39a038 |
12 | 24b533292b227 |
13 | c008135bc078 |
14 | 5452d7a6a7a7 |
15 | 2748cc29308a |
hex | 1390c6b5797f |
21512530000255 has 24 divisors (see below), whose sum is σ = 30197499703920. Its totient is φ = 14669038782720.
The previous prime is 21512530000249. The next prime is 21512530000289. The reversal of 21512530000255 is 55200003521512.
It is not a de Polignac number, because 21512530000255 - 25 = 21512530000223 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 245224986 + ... + 245312695.
It is an arithmetic number, because the mean of its divisors is an integer number (1258229154330).
Almost surely, 221512530000255 is an apocalyptic number.
21512530000255 is a deficient number, since it is larger than the sum of its proper divisors (8684969703665).
21512530000255 is a wasteful number, since it uses less digits than its factorization.
21512530000255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 490537879 (or 490537872 counting only the distinct ones).
The product of its (nonzero) digits is 15000, while the sum is 31.
Adding to 21512530000255 its reverse (55200003521512), we get a palindrome (76712533521767).
The spelling of 21512530000255 in words is "twenty-one trillion, five hundred twelve billion, five hundred thirty million, two hundred fifty-five", and thus it is an aban number.
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