Base | Representation |
---|---|
bin | 11111010011100110011… |
… | …110111100110111100111 |
3 | 21121200000022112221210202 |
4 | 133103212132330313213 |
5 | 240221431213140234 |
6 | 4324152231541115 |
7 | 311300320465166 |
oct | 37234636746747 |
9 | 7550008487722 |
10 | 2151350521319 |
11 | 75a42331365a |
12 | 2a8b42b2a79b |
13 | 127b4385a26c |
14 | 761a97533dd |
15 | 3ae6542b77e |
hex | 1f4e67bcde7 |
2151350521319 has 2 divisors, whose sum is σ = 2151350521320. Its totient is φ = 2151350521318.
The previous prime is 2151350521297. The next prime is 2151350521321. The reversal of 2151350521319 is 9131250531512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2151350521319 - 212 = 2151350517223 is a prime.
It is a super-2 number, since 2×21513505213192 (a number of 25 digits) contains 22 as substring.
Together with 2151350521321, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2151350521379) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075675260659 + 1075675260660.
It is an arithmetic number, because the mean of its divisors is an integer number (1075675260660).
Almost surely, 22151350521319 is an apocalyptic number.
2151350521319 is a deficient number, since it is larger than the sum of its proper divisors (1).
2151350521319 is an equidigital number, since it uses as much as digits as its factorization.
2151350521319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 38.
The spelling of 2151350521319 in words is "two trillion, one hundred fifty-one billion, three hundred fifty million, five hundred twenty-one thousand, three hundred nineteen".
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