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21522113 = 187111503
BaseRepresentation
bin101001000011…
…0011011000001
31111111102210022
41102012123001
521002201423
62045143225
7350635454
oct122063301
944442708
1021522113
111116a978
12725ab15
1345c71a2
142c0349b
151d51dc8
hex14866c1

21522113 has 4 divisors (see below), whose sum is σ = 21535488. Its totient is φ = 21508740.

The previous prime is 21522103. The next prime is 21522131. The reversal of 21522113 is 31122512.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21522113 - 216 = 21456577 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21522091 and 21522100.

It is not an unprimeable number, because it can be changed into a prime (21522103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3881 + ... + 7622.

It is an arithmetic number, because the mean of its divisors is an integer number (5383872).

Almost surely, 221522113 is an apocalyptic number.

It is an amenable number.

21522113 is a deficient number, since it is larger than the sum of its proper divisors (13375).

21522113 is a wasteful number, since it uses less digits than its factorization.

21522113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13374.

The product of its digits is 120, while the sum is 17.

The square root of 21522113 is about 4639.1931410537. The cubic root of 21522113 is about 278.1601866520.

Adding to 21522113 its reverse (31122512), we get a palindrome (52644625).

The spelling of 21522113 in words is "twenty-one million, five hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 1871 11503 21522113