Base | Representation |
---|---|
bin | 1100100010000110011… |
… | …0111001100001100111 |
3 | 202120202110220112211011 |
4 | 3020201212321201213 |
5 | 12011424411210043 |
6 | 242525115523051 |
7 | 21361431405511 |
oct | 3104146714147 |
9 | 676673815734 |
10 | 215312210023 |
11 | 8334a147229 |
12 | 3588b759487 |
13 | 173c474c791 |
14 | a5c7976bb1 |
15 | 59028aa59d |
hex | 32219b9867 |
215312210023 has 4 divisors (see below), whose sum is σ = 227977634160. Its totient is φ = 202646785888.
The previous prime is 215312209999. The next prime is 215312210081. The reversal of 215312210023 is 320012213512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 215312210023 - 237 = 77873256551 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 215312209976 and 215312210003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (215312210083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6332712043 + ... + 6332712076.
It is an arithmetic number, because the mean of its divisors is an integer number (56994408540).
Almost surely, 2215312210023 is an apocalyptic number.
215312210023 is a deficient number, since it is larger than the sum of its proper divisors (12665424137).
215312210023 is a wasteful number, since it uses less digits than its factorization.
215312210023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12665424136.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 215312210023 its reverse (320012213512), we get a palindrome (535324423535).
The spelling of 215312210023 in words is "two hundred fifteen billion, three hundred twelve million, two hundred ten thousand, twenty-three".
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