Base | Representation |
---|---|
bin | 1001110010101001011001… |
… | …11000110011000000001101 |
3 | 2211020101100222011102101102 |
4 | 10321110230320303000031 |
5 | 10310232324040010300 |
6 | 113443222200152445 |
7 | 4351410522316550 |
oct | 471245470630015 |
9 | 84211328142342 |
10 | 21531424141325 |
11 | 695147567195a |
12 | 24b8b26468725 |
13 | c02534b442b7 |
14 | 5461ab12a697 |
15 | 275135dbc0d5 |
hex | 13952ce3300d |
21531424141325 has 96 divisors (see below), whose sum is σ = 32995983360000. Its totient is φ = 13620806035200.
The previous prime is 21531424141319. The next prime is 21531424141421. The reversal of 21531424141325 is 52314142413512.
It is not a de Polignac number, because 21531424141325 - 24 = 21531424141309 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 11562476 + ... + 13294874.
It is an arithmetic number, because the mean of its divisors is an integer number (343708160000).
Almost surely, 221531424141325 is an apocalyptic number.
21531424141325 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
21531424141325 is a deficient number, since it is larger than the sum of its proper divisors (11464559218675).
21531424141325 is a wasteful number, since it uses less digits than its factorization.
21531424141325 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1732555 (or 1732550 counting only the distinct ones).
The product of its digits is 115200, while the sum is 38.
Adding to 21531424141325 its reverse (52314142413512), we get a palindrome (73845566554837).
The spelling of 21531424141325 in words is "twenty-one trillion, five hundred thirty-one billion, four hundred twenty-four million, one hundred forty-one thousand, three hundred twenty-five".
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