Base | Representation |
---|---|
bin | 1001110010101101010110… |
… | …00001110001111001100011 |
3 | 2211020120211110022210020221 |
4 | 10321112223001301321203 |
5 | 10310301142322102230 |
6 | 113444212155343511 |
7 | 4351514130404662 |
oct | 471265301617143 |
9 | 84216743283227 |
10 | 21533540425315 |
11 | 6952361212396 |
12 | 24b9417151b97 |
13 | c027b1414049 |
14 | 54632c214dd9 |
15 | 27520ba9e27a |
hex | 1395ab071e63 |
21533540425315 has 64 divisors (see below), whose sum is σ = 27295850188800. Its totient is φ = 16285168972800.
The previous prime is 21533540425289. The next prime is 21533540425339. The reversal of 21533540425315 is 51352404533512.
It is not a de Polignac number, because 21533540425315 - 25 = 21533540425283 is a prime.
It is a super-2 number, since 2×215335404253152 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 873240456 + ... + 873265114.
It is an arithmetic number, because the mean of its divisors is an integer number (426497659200).
Almost surely, 221533540425315 is an apocalyptic number.
21533540425315 is a deficient number, since it is larger than the sum of its proper divisors (5762309763485).
21533540425315 is a wasteful number, since it uses less digits than its factorization.
21533540425315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25348.
The product of its (nonzero) digits is 1080000, while the sum is 43.
Adding to 21533540425315 its reverse (51352404533512), we get a palindrome (72885944958827).
The spelling of 21533540425315 in words is "twenty-one trillion, five hundred thirty-three billion, five hundred forty million, four hundred twenty-five thousand, three hundred fifteen".
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