Base | Representation |
---|---|
bin | 1000000001011101… |
… | …1111000111011101 |
3 | 12120002110021020202 |
4 | 2000113133013131 |
5 | 13402312443123 |
6 | 553411553245 |
7 | 104240433011 |
oct | 20027370735 |
9 | 5502407222 |
10 | 2153640413 |
11 | a05745a11 |
12 | 5012bb825 |
13 | 28424c252 |
14 | 166050541 |
15 | c9110a28 |
hex | 805df1dd |
2153640413 has 2 divisors, whose sum is σ = 2153640414. Its totient is φ = 2153640412.
The previous prime is 2153640343. The next prime is 2153640449. The reversal of 2153640413 is 3140463512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1467043204 + 686597209 = 38302^2 + 26203^2 .
It is a cyclic number.
It is not a de Polignac number, because 2153640413 - 214 = 2153624029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2153645413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076820206 + 1076820207.
It is an arithmetic number, because the mean of its divisors is an integer number (1076820207).
Almost surely, 22153640413 is an apocalyptic number.
It is an amenable number.
2153640413 is a deficient number, since it is larger than the sum of its proper divisors (1).
2153640413 is an equidigital number, since it uses as much as digits as its factorization.
2153640413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 29.
The square root of 2153640413 is about 46407.3314574325. The cubic root of 2153640413 is about 1291.3909266489.
The spelling of 2153640413 in words is "two billion, one hundred fifty-three million, six hundred forty thousand, four hundred thirteen".
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