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2154240131 is a prime number
BaseRepresentation
bin1000000001100111…
…0001100010000011
312120010120201220112
42000121301202003
513402441141011
6553432501535
7104245511321
oct20031614203
95503521815
102154240131
11a0601554a
1250154a8ab
132843cc204
14166168d11
15c91cd58b
hex80671883

2154240131 has 2 divisors, whose sum is σ = 2154240132. Its totient is φ = 2154240130.

The previous prime is 2154240107. The next prime is 2154240149. The reversal of 2154240131 is 1310424512.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2154240131 - 210 = 2154239107 is a prime.

It is a super-2 number, since 2×21542401312 = 9281501084021794322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2154240097 and 2154240106.

It is not a weakly prime, because it can be changed into another prime (2154240161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077120065 + 1077120066.

It is an arithmetic number, because the mean of its divisors is an integer number (1077120066).

Almost surely, 22154240131 is an apocalyptic number.

2154240131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2154240131 is an equidigital number, since it uses as much as digits as its factorization.

2154240131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 23.

The square root of 2154240131 is about 46413.7924651714. The cubic root of 2154240131 is about 1291.5107854860.

Adding to 2154240131 its reverse (1310424512), we get a palindrome (3464664643).

The spelling of 2154240131 in words is "two billion, one hundred fifty-four million, two hundred forty thousand, one hundred thirty-one".