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215433425149 is a prime number
BaseRepresentation
bin1100100010100011010…
…1010011000011111101
3202121001220222220201021
43020220311103003331
512012201424101044
6242545125544141
721364432620415
oct3105065230375
9677056886637
10215433425149
1183401608a18
1235904275051
13174138b07c7
14a5d9acb645
15590d350e84
hex3228d530fd

215433425149 has 2 divisors, whose sum is σ = 215433425150. Its totient is φ = 215433425148.

The previous prime is 215433425147. The next prime is 215433425173. The reversal of 215433425149 is 941524334512.

215433425149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 209472813124 + 5960612025 = 457682^2 + 77205^2 .

It is a cyclic number.

It is not a de Polignac number, because 215433425149 - 21 = 215433425147 is a prime.

Together with 215433425147, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (215433425143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107716712574 + 107716712575.

It is an arithmetic number, because the mean of its divisors is an integer number (107716712575).

Almost surely, 2215433425149 is an apocalyptic number.

It is an amenable number.

215433425149 is a deficient number, since it is larger than the sum of its proper divisors (1).

215433425149 is an equidigital number, since it uses as much as digits as its factorization.

215433425149 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 518400, while the sum is 43.

The spelling of 215433425149 in words is "two hundred fifteen billion, four hundred thirty-three million, four hundred twenty-five thousand, one hundred forty-nine".