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2154556402133 is a prime number
BaseRepresentation
bin11111010110100101100…
…100011010100111010101
321121222021201222120112012
4133112211210122213111
5240300012414332013
64325442313034005
7311442626150402
oct37264544324725
97558251876465
102154556402133
11760818a13333
122a96986b5905
13128234aa7765
14763d142d2a9
153b0a1adc1a8
hex1f5a591a9d5

2154556402133 has 2 divisors, whose sum is σ = 2154556402134. Its totient is φ = 2154556402132.

The previous prime is 2154556402099. The next prime is 2154556402309. The reversal of 2154556402133 is 3312046554512.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2123729119204 + 30827282929 = 1457302^2 + 175577^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2154556402133 is a prime.

It is a super-2 number, since 2×21545564021332 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2154556422133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077278201066 + 1077278201067.

It is an arithmetic number, because the mean of its divisors is an integer number (1077278201067).

Almost surely, 22154556402133 is an apocalyptic number.

It is an amenable number.

2154556402133 is a deficient number, since it is larger than the sum of its proper divisors (1).

2154556402133 is an equidigital number, since it uses as much as digits as its factorization.

2154556402133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432000, while the sum is 41.

The spelling of 2154556402133 in words is "two trillion, one hundred fifty-four billion, five hundred fifty-six million, four hundred two thousand, one hundred thirty-three".