Search a number
-
+
21550433312455 = 54310086662491
BaseRepresentation
bin1001110011001100110011…
…11011000001111011000111
32211022012102202021100221121
410321212121323001323013
510311040241411444310
6113500044332454411
74352652553520545
oct471463173017307
984265382240847
1021550433312455
11695953a871543
12250075061a407
13c04274173258
145470919b0d95
15275899b690da
hex139999ec1ec7

21550433312455 has 4 divisors (see below), whose sum is σ = 25860519974952. Its totient is φ = 17240346649960.

The previous prime is 21550433312449. The next prime is 21550433312459. The reversal of 21550433312455 is 55421333405512.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-21550433312455 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21550433312459) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2155043331241 + ... + 2155043331250.

It is an arithmetic number, because the mean of its divisors is an integer number (6465129993738).

Almost surely, 221550433312455 is an apocalyptic number.

21550433312455 is a deficient number, since it is larger than the sum of its proper divisors (4310086662497).

21550433312455 is an equidigital number, since it uses as much as digits as its factorization.

21550433312455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4310086662496.

The product of its (nonzero) digits is 1080000, while the sum is 43.

Adding to 21550433312455 its reverse (55421333405512), we get a palindrome (76971766717967).

The spelling of 21550433312455 in words is "twenty-one trillion, five hundred fifty billion, four hundred thirty-three million, three hundred twelve thousand, four hundred fifty-five".

Divisors: 1 5 4310086662491 21550433312455